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Spring Force Calculator

The spring force calculator uses Hooke s law to compute the elastic force F = k * x and the elastic potential energy E = 0.5 * k * x^2. If you enter a load mass, it also returns the static deflection x = m * g / k and the harmonic oscillation period T = 2 * PI * sqrt(m / k).

Reviewed byRedakcja Liczbnik
Calculator
Calculation resultElastic force F [N]10N
Potential energy E [J]
0.5 J

Hooke s law formulas

Elastic force: F = k * x Elastic potential energy: E = 0.5 * k * x^2 Static deflection from mass: x = m * g / k (g = 9.81 m/s^2) Harmonic oscillation period: T = 2 * PI * sqrt(m / k) k is the spring constant [N/m], x is the deformation [m], m is the load mass [kg]. The force opposes the deformation (restoring force); here we report its numeric value.

Example: spring k = 200 N/m, x = 0.1 m

For a spring constant k = 200 N/m and extension x = 0.1 m the elastic force is F = 200 * 0.1 = 20 N and the potential energy is E = 0.5 * 200 * 0.1^2 = 1 J. Hanging a mass m = 1 kg gives a static deflection x = 1 * 9.81 / 200 ~ 0.049 m.

Frequently asked questions

What is Hooke s law?

Hooke s law states that the elastic force is directly proportional to the deformation: F = k * x. The constant k (spring constant) describes the stiffness in newtons per metre (N/m). It holds within the elastic range, while the material returns to its original shape after the force is removed.

How do I calculate the spring force?

Use F = k * x, where k is the spring constant [N/m] and x is the deformation in metres. Example: for k = 500 N/m and x = 0.04 m the force is F = 500 * 0.04 = 20 N.

What does the spring constant k mean?

The spring constant k tells you how stiff the spring is — how many newtons are needed to stretch it by one metre. The larger k, the stiffer the spring. The unit is N/m; a spring with k = 1000 N/m is ten times stiffer than one with k = 100 N/m.

How do I calculate elastic potential energy?

Use E = 0.5 * k * x^2. This is the work done deforming the spring and the energy stored in it. Example: k = 200 N/m, x = 0.1 m gives E = 0.5 * 200 * 0.01 = 1 J.

Why does energy grow with the square of deformation?

In E = 0.5 * k * x^2 the deformation is squared because the force grows linearly with x and energy is the area under the force-distance graph (a triangle). Doubling the deformation quadruples the energy rather than doubling it.

How does mass affect spring deflection?

A hanging load stretches the spring until the elastic force balances the weight: k * x = m * g. Hence the static deflection x = m * g / k, with g = 9.81 m/s^2. A larger mass or a smaller k means a bigger extension.

Indicative result

The calculator assumes an ideal spring obeying Hooke s law (linear force-deformation relation) and ignores the spring s own mass and friction. For large deformations or non-linear springs the results are approximate.
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